Madonna, Macklemore & Ryan Lewis to Perform "Same Love" Together at the 2014 Grammys
Let the fun begin! The Grammy Awards are well known for organizing surprise collaborations between huge artists in the music industry, and this year is no exception. Madonna and Macklemore & Ryan Lewis will be taking the stage together at the Staples Center in L.A. for the 2014 Grammys, sources confirm to Us Weekly.
Madonna, 55, and 30-year-old Ben Haggerty -- who goes by the name Macklemore alongside his producer Lewis, 25 -- will be performing the rap duo's 2013 hit "Same Love." (Us previously reported the Queen of Pop and gay icon would be providing guest vocals for one of the evening's nominees. Her appearance was officially confirmed Friday.) "Same Love" is an anthem for LGBT equality and same sex marriage.
This has been a hugely successful year for the old friends, who won for both Favorite Rap/Hip-Hip Artist and Favorite Rap/Hip-Hip Album at the 2013 American Music Awards last November. At the Grammys on Jan. 25, they are up for seven nominations -- including Album of the Year for The Heist, Song of the Year for "Same Love," and Best New Artist.
The "Material Girl" herself, meanwhile, hinted earlier this week that she would be performing during the live show. "My lips are almost sealed! I can't say anything more. #itsasecret," she wrote on Friday, Jan. 24, with a picture of herself covered up in a thin black veil.
She added: "It's official! I'm off my crutches and I'm looking for the perfect pair of heels to wear to the Grammys." (Last Thursday, the seven-time Grammy winner sustained a minor injury from dancing in high heels.)
The 56th Annual Grammy Awards will air on Sunday, Jan. 26 at 8 p.m. EST on CBS.